An electric device delivers a current of [tex]$15.0 A$[/tex] for 30 seconds. How many electrons flow through it?
Answer (2)
Let's address each part of the question step by step:
2345 + 0 = ...
The additive identity property tells us that any number plus zero equals the original number. Therefore, 2345 + 0 = 2345 .
If 889 + 1 = 890, then 890 is the successor of ...
The successor of a number is obtained by adding 1 to it. Since 889 + 1 = 890 , 890 is the successor of 889.
5293 + 625 = ... + 5293
According to the commutative property of addition, the numbers can swap places without changing the result. Therefore, 5293 + 625 = 625 + 5293 .
3291 + 3053 + 108 = 3053 + ... + 108
By the commutative property of addition, the order can be rearranged. This means 3291 + 3053 + 108 = 3053 + 3291 + 108 .
2569 + ... = 2569
According to the additive identity property, adding zero to a number yields the number itself. So, 2569 + 0 = 2569 .
1096 + 2189 + 4443 = 4443 + ... + 2189
Using the commutative property again, 1096 + 2189 + 4443 = 4443 + 1096 + 2189 .
If 9000 is the successor of 8999, then ... + 1 = 9000
The successor of a number minus one gives the original number. Thus, 8999 + 1 = 9000 .
3210 + ... + ... = 2345 + 6789 + ...
If we want equality, then 2345 + 6789 − 3210 should give the remaining sum when the other expressions are equal. However, since the exact terms are not specified for the second sum, this would need more context to solve.
... + 2056 = ... + 6873
Without additional information, this part seems to be exploratory or missing details. Normally, adding numbers should equate when sums are structured equivalently.
4640 + 2020 = ... + 4640
Using the commutative property of addition, [tex]4640 + 2020 = 2020 + 4640[/tex].
0 + 6936 = ...
The additive identity property tells us that zero plus any number equals the number itself. Therefore, [tex]0 + 6936 = 6936[/tex].
8621 + ... = 8621
According to the additive identity property, [tex]8621 + 0 = 8621[/tex].
To find out how many electrons flow through a device with a current of 15.0 A for 30 seconds, you calculate the total charge using the formula Q = I × t , which gives you 450 coulombs. Then, using the charge of an electron (approximately 1.6 × 1 0 − 19 coulombs), you find that about 2.81 × 1 0 21 electrons pass through the device. Therefore, approximately 2.81 × 1 0 21 electrons flow in that time period.
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