Match the column:
Column-I | Column-II
---|---
(a) Unit digit of (36)^2 | (p) 1
(b) Number of zeroes in square of 300 | (q) 7
(c) A number that ends in ___ is never a perfect square. | (r) 6
(d) Unit digit in square of 89 | (s) 4
(1) a-s, b-p, c-q, d-r
(2) a-r, b-p, c-q, d-s
(3) a-s, b-p, c-q, d-p
(4) a-r, b-s, c-q, d-p
Answer (1)
To solve the given problem, let's analyze each part of the matching question:
(a) Unit digit of ( 36 ) 2 : To find the unit digit of a square, it's sufficient to look at the unit digit of the original number and square it. The unit digit of 36 is 6. When we square it, 6 2 = 36 . Therefore, the unit digit is 6.
(b) Number of zeroes in square of 300 : When we square 300, 30 0 2 = 90000 . In 90000, there are three zeroes at the end of the number.
(c) A number that ends in ___ is never a perfect square : A perfect square can never end in 2, 3, 7, or 8. So, the answer is 7.
(d) Unit digit in square of 89 : The unit digit of 89 is 9. Squaring it gives 9 2 = 81 . Thus, the unit digit is 1.
Now we can match the columns:
(a) matches with (r) because the unit digit of ( 36 ) 2 is 6.
(b) matches with (s) because the number of zeroes in the square of 300 is 4.
(c) matches with (q) because a number ending in 7 is never a perfect square.
(d) matches with (p) because the unit digit in the square of 89 is 1.
Therefore, the correct matching is option (4): a-r, b-s, c-q, d-p.
