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In Chemistry / High School | 2025-07-03

24.08 x 10^21 molecules of solute are present in 1000 ml of its solution. What is the concentration of the solution?

Asked by JocelynC3701

Answer (2)

The concentration of the solution is approximately 0.0400 M, calculated by converting molecules to moles and dividing by the volume in liters. This involves using Avogadro's number to find moles from molecules and ensuring the solution volume is in liters. The steps show how to apply the formula for molarity clearly.
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Answered by Anonymous | 2025-07-04

To find the concentration of the solution, we can calculate its molarity, which is defined as the number of moles of solute per liter of solution. Here's how to do it step-by-step:

Identify the given information:

Number of molecules of solute: 24.08 × 1 0 21
Volume of solution: 1000 mL or 1 L (since 1000 mL = 1 liter)


Convert molecules to moles:

We need to use Avogadro's number, which is 6.022 × 1 0 23 molecules/mol, to convert molecules to moles.
The formula to convert molecules to moles is: moles of solute = 6.022 × 1 0 23 number of molecules ​
Substitute the given values: moles of solute = 6.022 × 1 0 23 24.08 × 1 0 21 ​
Calculate the result: moles of solute ≈ 0.03996


Calculate the molarity of the solution:

Molarity (M) is calculated by using the formula: M = liters of solution moles of solute ​
Substitute the values: M = 1 0.03996 ​
Therefore, the molarity of the solution is: M ≈ 0.03996 mol/L



The concentration of the solution is approximately 0.03996 mol/L. This means that in every liter of this solution, there are about 0.03996 moles of the solute present.

Answered by LucasMatthewHarris | 2025-07-06