A person opens a door by applying a 10-N force perpendicular to it at a distance of 0.90 m from the hinges. What is the torque applied to the door?

You faded out there before asking your question. Here's some info that might be of interest:
Torque = (force) x (distance from the pivot) = (10 n) x (0.9 m) = 9 newton-meters

Answered by AL2006 | 2024-06-10

The torque applied to the door is calculated using the formula τ = F × r and is equal to 9 N ⋅ m when a 10-N force is applied at a distance of 0.90 m from the hinges. Torque is a measure of rotational force. In this case, since the force is applied perpendicularly, the calculation is straightforward.
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Answered by AL2006 | 2024-12-24