How much time is needed for a car to accelerate from 8.0 m/s to a speed of 22 m/s if the acceleration is 3.0 m/s²?
Answer (3)
acceleration = (final velocity - initial velocity)/ time taken so, time taken = (final velocity - initial velocity)/ acceleration = (22-8)/3 = 4.67 seconds
The **time **needed to accelerate the car from **8.0 **m/s to a speed of 22 m/s will be **4.67 **seconds.
What is acceleration?
Acceleration of any **object **is defined as the variation in the speed of the object with the variation of the time. Acceleration is a **vector **term and to define it we **require **both the magnitude and the direction. The **unit **of the acceleration can be m / sec², miles / sec², etc.
Given that, for a **car **to accelerate from **8.0 **m/s to a speed of **22 **m/s the required acceleration is **3.0 **m/s²
The time to **accelerate **the car will be **calculated **as below:-
Acceleration = (final velocity - initial velocity)/ time taken
Time taken = (final velocity - initial velocity)/ acceleration
Time taken = (22-8)/3 = 4.67 seconds
Therefore, the **time **needed to accelerate the car from **8.0 **m/s to a speed of 22 m/s will be **4.67 **seconds.
To know more about **acceleration **follow
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The time needed for a car to accelerate from 8.0 m/s to 22 m/s at an acceleration of 3.0 m/s² is approximately 4.67 seconds. This is calculated using the formula for acceleration rearranged to solve for time. By substituting the initial and final velocities and acceleration into this formula, we determine the time required for the acceleration to occur.
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