What is the mass of 4.2 moles of sodium carbonate?
Answer (3)
4.2 mol Na2CO3 x 83g = 348.6g Na2CO3 1 1 mol
To calculate the mass of 4.2 moles of sodium carbonate (Na₂CO₃), we must first find the molar mass of the compound. The molar mass is the sum of the atomic masses of all atoms in the molecule. Sodium (Na) has an atomic mass of 23.0 g/mol, carbon (C) has 12.0 g/mol, and oxygen (O) has 16.0 g/mol.
Step 1: Calculate the molar mass of Na₂CO₃. It consists of 2 atoms of sodium, 1 atom of carbon, and 3 atoms of oxygen. Therefore, the molar mass is (2×23.0) + 12.0 + (3×16.0) = 106 g/mol.
Step 2: Multiply the molar mass by the number of moles to get the mass. The mass of 4.2 moles of NaCO₃ is 4.2 moles × 106 g/mol = 445.2 grams.
The mass of 4.2 moles of sodium carbonate (Na₂CO₃) is calculated by first finding its molar mass, which is 106.0 g/mol. Multiplying by the number of moles gives a total mass of 445.2 grams. Thus, 4.2 moles of Na₂CO₃ weighs 445.2 grams.
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