The larger of two numbers is 1 more than twice the smaller. The sum of the numbers is 20 less than three times the larger. Find the numbers.

Let x be the larger number; Let y be the smaller number. EQUATIONS: x-2y=1 x+y+20=3x
Rewrite as x-2y=1 2x-y=20





Multiply the 1st equation by 2 to get:
2x-4y=2
Subtract this result from the 1st equation to get:
3y=18
y=6
Substitute that into the 1st equation to get:
x-2*6=1
x=13
-------
Solution: x=13; y=6

Answered by aunapetitbabysi | 2024-06-10

13 and 6 ;

Answered by kevans2022 | 2024-06-12

The larger number is 13 and the smaller number is 6. These values satisfy both conditions given in the problem. The relationships were defined through two equations and solved step-by-step.
;

Answered by aunapetitbabysi | 2024-12-17