Which value is a zero of the function defined by \(6x^2 + 6x - 36\)?
Answer (2)
Only solve the equation:
6 x 2 + 6 x − 36 = 0 Δ = 6 2 − 4.6. ( − 36 ) = 36 + 864 = 900 x = 2.6 − 6 ± 900 = 12 − 6 ± 30 x 1 = 12 − 36 = − 3 x 2 = 12 24 = 2
Zeros of this function are: -3 and 2
The zeros of the function 6 x 2 + 6 x − 36 are -3 and 2, found using the quadratic formula. By applying the formula to calculate the roots, we derived these two values as solutions to the equation. These zeros indicate where the function intersects the x-axis.
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