A. We know that the height (h) = 25 m, and the distance (x) = 135 m.
B. We need to find the time flight first (t), then we can find easily the horizontal velocity ( v x . )
C. Because this is a projectile motions, so horizontal velocity is constant, but the vertical velocity is change because of the gravitational acceleration. So we can use : h = 2 1 g t 2 ,
Note : Time that will be exist is a time from a land to the takeoff point, that can be called as the time flight. Then we use, x = v x t , to find the horizontal velocity.
D. We know that : h = 2 1 g t 2 , so by insert the numbers, and assune that the (g = 10 m/ s 2 ), we get that ( t = 5 . ) After that by using x = v x t , we can get that v x = 27 5
The ski jumper needs to leave the jump with an approximate speed of 59.47 m/s to cover a horizontal distance of 135 meters from a height of 25 meters. We used the physics formula for **horizontal displacement **in projectile motion to solve this problem. ;
The ski jumper must achieve a horizontal speed of approximately 60.27 m/s to cover 135 meters while starting from a height of 25 meters. This was calculated using the equations for projectile motion. The time of flight was first determined based on the height of the jump, and then used to calculate the required horizontal speed.
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