M N 2 = 28 g / m o l 63 , 8% − − 28 g 100% − − x x = 43 , 89 g
43,89g≈44g 44g == 2x ****14g (**N) **+ 1x 16x( O )
**M N₂O = 44g
**
The empirical formula for the compound containing 63.8% nitrogen and 36.2% oxygen is N₂O, derived by calculating moles and simplifying their ratios to whole numbers. Therefore, the correct answer is E: N₂O.
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