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In Chemistry / High School | 2014-04-30

1. What is the empirical formula for a compound containing 63.8% N and 36.2% O?

A. N₂O₅
B. N₂O₃
C. NO₂
D. NO
E. N₂O

Asked by Rocky254

Answer (2)

M N 2 ​ = 28 g / m o l 63 , 8% − − 28 g 100% − − x x = 43 , 89 g
43,89g≈44g 44g == 2x ****14g (**N) **+ 1x 16x( O )
**M N₂O = 44g
**

Answered by marmal | 2024-06-10

The empirical formula for the compound containing 63.8% nitrogen and 36.2% oxygen is N₂O, derived by calculating moles and simplifying their ratios to whole numbers. Therefore, the correct answer is E: N₂O.
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Answered by Anonymous | 2024-10-02