You kick a ball with a speed of 14 m/s at an angle of 51 degrees. How far away does the ball land?

A. 21.3 m
B. 19.6 m
C. 1.8 m
D. 3.96 m

d may be the correct answer because speed is very low so ball should cover less distance but angle is not very high so it can cover little much distance

Answered by nehal | 2024-06-10

To calculate the horizontal range of the ball, we use the formula:
R = g v 2 sin 2 θ ​
where,
v = velocity of the ball = 14 m/s
θ = angle at which the ball is thrown = 51°
g = acceleration due to gravity = 9.8 m / s 2
Putting values in above equation, we get:
R = 9.8 ( 14 ) 2 × sin ( 2 × 51 ) ​ R = 19.6 m
Hence, the ball will land at 19.6 m

Answered by Anonymous | 2024-06-12

The range of the ball kicked at 14 m/s and an angle of 51 degrees is approximately 19.34 m. Therefore, the correct multiple choice answer is B. 19.6 m.
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Answered by Anonymous | 2024-10-01