Boron found in nature has an atomic weight of 10.811 and is made up of the isotopes [tex]^{10}B[/tex] (mass 10.013 amu) and [tex]^{11}B[/tex] (mass 11.0093 amu). What percentage of naturally occurring boron is made up of [tex]^{10}B[/tex] and [tex]^{11}B[/tex] respectively?
a. 30:70
b. 25:75
c. 20:80
d. 15:85
Asked by Scutt223
Answer (1)
C 20:80 because the equation would be (10×.2)+(11×.8)