What is the molar mass of the following compound, rounded to the nearest gram?
\[ \text{Na}_2\text{S}_2\text{O}_3 \]
Answer (3)
mass of Na = 23 u mass of S = 32 u mass of oxygen = 16 u
Thus, Na2S2O3
= 23(2) + 32(2) + 16(3)
= 46 + 64 + 48
= 110 + 48 = 158 u.
The molar mass of Na₂S₂O₃ is 158 g/mol.
To find the molar mass of Na₂S₂O₃, we need to add up the atomic masses of all the atoms in the compound.
The atomic masses are as follows:
Sodium (Na): 23.0 g/mol
Sulfur (S): 32.0 g/mol
Oxygen (O): 16.0 g/mol
The compound Na₂S₂O₃ has:
2 Sodium (Na) atoms: 2 x 23.0 g/mol
2 Sulfur (S) atoms: 2 x 32.0 g/mol
3 Oxygen (O) atoms: 3 x 16.0 g/mol
Adding these together:
(2 x 23.0) + (2 x 32.0) + (3 x 16.0) = 46.0 + 64.0 + 48.0 = 158.0 g/mol
Thus, the molar mass of Na₂S₂O₃, rounded to the nearest gram, is 158 g/mol.
The molar mass of the compound Na 2 S 2 O 3 is calculated by summing the atomic masses of its components, resulting in approximately 158 g/mol.
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