Balance the equation:
\(...NO_2 + ...O_2 + ...H_2O = ...HNO_3\)
Answer (2)
We are going to do this by means of electronic balance: N(IV)\Rightarrow\ N(V)+e^-|*4\\
2O(0)+4e^-\Rightarrow\ 2O^2^-\\
4NO_2+O_2+2H_2O\Rightarrow4HNO_3
If you hadn't learnt it yet, you would do it normally: Count oxygens. To have even number of oxygen write "2" in fronf of H2O. Then to have equal hydrogen you have to add "4" in front of HNO3 and then NO2.
The balanced chemical equation for the reaction is 4NO₂ + O₂ + 2H₂O = 4HNO₃. To achieve this, coefficients are systematically adjusted based on the number of atoms of each element on both sides of the equation. This ensures that the law of conservation of mass is upheld, meaning all atoms are accounted for evenly on each side.
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