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In Chemistry / High School | 2014-04-25

A test tube containing CaCO₃ is heated until the entire compound decomposes. If the test tube plus calcium carbonate originally weighed 30.08 grams and the loss of mass during the experiment was 4.40 grams, what was the approximate mass of the empty test tube?

A. 20.08 g
B. 21.00 g
C. 24.50 g
D. 25.08 g
E. 25.68 g

Asked by VernellFonder

Answer (2)

To determine the mass of the empty test tube, we need to consider the initial total mass of the test tube plus calcium carbonate ( CaCO3 ) and the amount of mass lost during the experiment. The initial total mass was given as 30.08 grams. After heating, CaCO3 decomposed, resulting in a loss of 4.40 grams, which was the mass of carbon dioxide ( CO2 ) gas released.
To find the mass of the empty test tube, we subtract the mass of the CaCO3 that decomposed (the lost mass) from the initial total mass:
Mass of empty test tube = Initial total mass - Mass of CO2 released
= 30.08 g - 4.40 g
= 25.68 grams
Therefore, the mass of the empty test tube is 25.68 grams, which corresponds to option E.

Answered by PhilDavis | 2024-06-18

The mass of the empty test tube is calculated by subtracting the mass loss (4.40 grams) during the decomposition of calcium carbonate from the initial total mass (30.08 grams), resulting in a mass of 25.68 grams. Therefore, the correct answer is option E.
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Answered by PhilDavis | 2024-09-05