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In Chemistry / High School | 2014-04-20

Pick the answer that most likely represents the substances’ relative solubilities in water.

A. CH₃CH₂CH₂CH₃ < CH₃CH₂CH₂OH < HOCH₂CH₂OH
B. CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH
C. CH₃CH₂CH₂CH₃ < HOCH₂CH₂OH < CH₃CH₂CH₂OH
D. HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃
E. HOCH₂CH₂OH < CH₃CH₂CH₂OH < CH₃CH₂CH₂CH₃

Asked by Probst105

Answer (3)

the naswer should be A

Answered by joporto | 2024-06-10

The correct answer for substances relative solubilities in water is option (A) CH₃CH₂CH₂CH₃ < CH₃CH₂CH₂OH < HOCH₂CH₂OH.
To determine the relative solubilities of these compounds in water, we need to consider hydrogen bonding and polarity:

CH₃CH₂CH₂CH₃ (Butane): This is a nonpolar molecule without any hydrogen bonding capability, making it the least soluble in water.
CH₃CH₂CH₂OH (Propanol): This has an -OH group allowing for hydrogen bonding, making it more soluble than butane.
HOCH₂CH₂OH (Ethylene glycol): This has two -OH groups, which significantly increases its ability to hydrogen bond, making it the most soluble in water among the three.

The compounds rank in solubility in water as Butane < Propanol < Ethylene Glycol due to the increasing ability to participate in hydrogen bonding.

Answered by IanMckellen | 2024-06-24

The relative solubility of the mentioned substances in water is determined by their ability to form hydrogen bonds. The correct ranking from least to most soluble is Butane < Propanol < Ethylene Glycol, which corresponds to option A. This reflects how the presence of hydroxyl groups enhances solubility due to hydrogen bonding capabilities.
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Answered by IanMckellen | 2024-12-20