Sr^(2+) = 36 Rb = 37 Cl^(-) = 18 Kr = 36
So the one with the most is (B) Rb
Rubidium (Rb) has the most electrons with a total of 37, compared to Strontium ion (Sr²⁺) and Krypton (Kr), which both have 36 electrons, and Chlorine ion (Cl⁻), which has 18 electrons. Thus, the answer is B) Rb.
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