Iron(III) sulfite has the formula

a) Fe₃SO₃
b) Fe₂(SO₄)₃
c) Fe₂(SO₃)₃
d) Fe₂SO₄
e) Fe₂SO₃

option C= Fe2(SO3)3 interchanged oxidation number[Fe]3+[SO3]2-

Answered by jydclix | 2024-06-10

The correct formula for Iron(III) sulfite, considering the charge balance between iron(III) cations and sulfite anions, is Fe2(SO3)3.
The formula for Iron(III) sulfite is derived from the iron(III) ion having a +3 charge and the sulfite ion (SO32-) having a -2 charge. To achieve a neutral compound, you need two iron(III) cations to balance three sulfite anions, thus the correct formula is Fe2(SO3)3.

Iron has a +3 charge as indicated by the (III).
Sulfite is the polyatomic ion SO3 with a -2 charge.
For neutrality, the charges must balance, so we need two Fe3+ and three SO32-.

Answered by EvaSharma1 | 2024-06-25

The correct formula for iron(III) sulfite is F e 2 ​ ( S O 3 ​ ) 3 ​ , which is option c. This formula balances the charges of the iron and sulfite ions properly. It consists of 2 iron ions in the +3 oxidation state and 3 sulfite ions, resulting in a neutral compound.
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Answered by jydclix | 2024-09-05