2 m³ of soil containing 35% sand was mixed into 6 m³ of soil containing 15% sand. What is the sand content of the mixture?

answer is: 1.6 m3 of sand

Answered by andreigafton | 2024-06-10

To find the sand content of the mixture, we first calculate the total amount of sand in each volume of soil and then combine them to find the overall percentage in the mixture.
For the 2 m^3 soil with 35% sand:
Amount of sand = 2 m^3 times 0.35 = 0.7 m^3 of sand
For the 6 m^3 soil with 15% sand:
Amount of sand = 6 m^3 times 0.15 = 0.9 m^3 of sand
Total amount of sand in the mixture = 0.7 m^3 + 0.9 m^3 = 1.6 m^3
Total volume of the mix = 2 m^3 + 6 m^3 = 8 m^3
Percentage of sand in the mixture = (Total amount of sand / Total volume of the mix) times 100
Percentage of sand in the mixture = (1.6 m^3 / 8 m^3) times 100 = 20%
Therefore, the sand content of the mixture is 20%.

Answered by Qwcold | 2024-06-24

The sand content of the mixture is calculated to be 20%. This was determined by finding the total amounts of sand from the individual soil volumes and then dividing that by the total volume of the mixture. The final percentage of sand is 20%.
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Answered by Qwcold | 2024-12-27