A single-cell amoeba doubles every 3 days. How long would it take one amoeba to produce a population of about 10,000 amoebae?

2^n=10,000 2^14=10,000 d=3n d=3(14) d=42
d=days n=number of times of reproduction

Answered by runescapememo8 | 2024-06-10

It would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae. ;

Answered by JoanBlondell | 2024-06-18

It would take approximately 42 days for a single-cell amoeba to produce a population of about 10,000 amoebae, considering that the amoeba doubles every 3 days. The amoeba would need to double 14 times to reach this population size. Thus, the total time is 14 doubling periods multiplied by 3 days each, resulting in 42 days.
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Answered by JoanBlondell | 2024-10-01