The legs of a right triangle have lengths of 28 meters and 21 meters. The hypotenuse has a length of [tex]5x[/tex] meters. What is the value of [tex]x[/tex]?

a = 21 m , b = 28 m , c = 5 x m c 2 = a 2 + b 2 ( 5 x ) 2 = 2 1 2 + 2 8 2 25 x 2 = 441 + 784 25 x 2 = 1225/ : 25 x 2 = 49 x = 49 ​ x = 7 m

Answered by Anonymous | 2024-06-10

The value of x of a triangle that has the legs of lengths 28 meters and 21
meters and the hypotenuse of 5x meters is** 7 **
The triangle is a right angle triangle .
Using Pythagoras theorem, let's find the** hypotenuse side **and invariably the value of x
c² =a² + b²
(5x)² = 28² + 21²
25x² = 784 + 441
25x² = 1225
square root both sides
5x = √1225
5x = 35
divide both sides by 5
5x / 5 = 35 / 5
x = 7
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Answered by vintechnology | 2024-06-24

The value of x in the right triangle is 7. This was determined using the Pythagorean theorem by finding the hypotenuse based on the lengths of the legs. The calculations showed that 5x is equal to 35 meters.
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Answered by vintechnology | 2024-10-30