In the presence of oxygen, one glucose molecule has the energy to make up to
A. 12 NADH
B. 4 FADH\(_2\)
C. 38 ATP
D. All of the above
Answer (3)
**C. 38 ATP
**
In the presence of oxygen, one glucose molecule has the energy to make up to 38 ATP. The ATP production is determined by the following steps, (-2 ATP) glycolysis preparatory phase, (7-9 ATP) glycolysis pay-off phase, (5 ATP) oxidative decarboxylation of pyruvate and (20 ATP) Krebs cycle. One glucose which has 38 ATP hence was the summation of all the process mentioned that took place. All these process take place under the cellular function of cellular respiration.
In aerobic respiration, one molecule of glucose has the energy to produce up to 38 ATP molecules. This process involves glycolysis, the Krebs Cycle, and the electron transport chain (ETC). During this process,
12 NADH are produced, which contribute to the generation of approximately 36 ATP through oxidative phosphorylation.
4 FADH2 molecules are also generated, which ultimately result in the production of around 8 ATP.
Adding these together, plus 4 ATP directly generated from glycolysis and the Krebs Cycle, totals up to 38 ATP molecules. However, the actual number of ATP produced can be slightly lower than this theoretical maximum, mainly due to the energy cost of transporting intermediates into the mitochondria.
One glucose molecule can produce a theoretical maximum of 38 ATP during aerobic respiration. This involves glycolysis, the Krebs cycle, and the electron transport chain, resulting in the generation of ATP from NADH and FADH\textsubscript{2}. Thus, the correct answer is C. 38 ATP.
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