2 s in x cos x + cos x = 0 cos x ( 2 s in x + 1 ) = 0 āŗ cos x = 0 ⨠2 s in x + 1 = 0 cos x = 0 ⨠2 s in x = ā 1 / : 2 cos x = 0 ⨠s in x = ā 2 1 ā x = 2 Ļ ā + kĻ āØ x = ā 6 Ļ ā + 2 kĻ āØ x = 6 7 Ļ ā + 2 kĻ t o k ā Z
To solve the equation 2 sin x cos x + cos x = 0 , we factor it to find two conditions: cos x = 0 and sin x = ā 2 1 ā . This gives us multiple solutions depending on the integer k .
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