Anne has 24 more cards than Devi. Anne finds that [tex]\frac{3}{5}[/tex] of Devi's cards are equal to [tex]\frac{1}{2}[/tex] of her cards. How many cards does Anne have?

LET ANNE HAS X NUMBER OF CARDS LET DEVI HAS Y NUMBER OF CARDS X-Y= 24 ------EQ 1 3/5Y=1/2X 6Y=5X (cross multiplying)-------EQ 2 FROM EQ 1 WE GET X=24+Y substituting the value of x in eq 2, we get 6y=5(24+y) 6y =120+5y y= 120
NOW, PUTTING THE VALUE OF Y IN EQ 1 X-120=24 X=24+120 X=144 THEREFORE, ANNE HAS 144 CARDS

Answered by Anonymous | 2024-06-10

a=Anne's cards D= Devi's cards d+24=a 3d/5=a/2 6d/5=a 6d/5=d+24 6d/5-d=24 6d-5d=120 d=120 a=144

Answered by HannahN | 2024-06-10

Anne has 144 cards. This was found by establishing two equations based on the relationship between the number of cards she has compared to Devi. By solving these equations, we determined that Devi has 120 cards, leading us to conclude that Anne has 144 cards.
;

Answered by Anonymous | 2024-10-01