There were about 340,000 cattle placed on feed.

1. Write an equivalent ratio that could be used to find how many of these cattle were between 700-799 pounds.
2. How many of the 340,000 cattle placed on feed were between 700-799 pounds?

Weight Group Fraction of Total Cattle
less than 600 pounds \(\frac{1}{5}\)
600-699 pounds \(\frac{11}{50}\)
700-799 pounds \(\frac{2}{5}\)
800 pounds \(\frac{9}{20}\)

The correct answer is:
An equivalent ratio would be 4/10, and the number of cattle would be 136,000.
Explanation :
The question asks for an equivalent ratio. This means a fraction that is equivalent to the fraction between 700-799, which is 2/5.
To create an equivalent fraction, we multiply the numerator and denominator by the same number. Multiplying both by 2, we get
(2 2)/(5 2) = 4/10.
Tenths are useful when dealing with thousands, because taking a tenth involves getting rid of a zero. This means that 1/10 would be 34000; 4/10 would be 4 times that: 4(34000) = 136000.

Answered by MsEHolt | 2024-06-11

136,000 cattle ;

Answered by teeteeyong | 2024-06-15

The equivalent ratio for the cattle between 700-799 pounds is 10 4 ​ . There are 136,000 cattle that fall within this weight range out of the total of 340,000 cattle placed on feed.
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Answered by MsEHolt | 2024-09-26