3/5*n=1
Therefore n=5/3=3/3+2/3=1+2/3
3/5*x=2
3x=10
x=10/3=9/3+1/3=3+1/3
a ) 5 3 1 = 1 ∗ 3 5 = 3 5 T h ere a re 1 3 2 o f 5 3 s in 1. b ) 5 3 2 = 2 ∗ 3 5 = 3 10 T h ere a re 3 3 1 o f 5 3 s in 2.
To find how many 5 3 are in 1, we calculate 3 5 . For 2, it results in 3 10 . Hence, there are 1 3 2 of 5 3 in 1 and 3 3 1 in 2.
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