Find the prime factorization of 525 in expanded form.
Answer (2)
To find the prime factorization of 525 in expanded form, we need to break down the number into its prime factors. First, we can divide 525 by the smallest prime number, which is 2, but since 525 is odd, we move on to the next prime number, which is 3. We find that 525 is not divisible by 3 either, so we move on to 5. Now, 525 is divisible by 5 because it ends in a 5 or 0. Dividing 525 by 5, we get 105. We can divide 105 by 5 again to get 21. The number 21 is divisible by 3, and we get 7. Since 7 is a prime number, we stop the process. The prime factorization of 525 is therefore 5 x 5 x 3 x 7 or, written in exponential form, 5² x 3 x 7.
The prime factorization of 525 is 5 2 × 3 × 7 in expanded form. We find this by dividing 525 by prime numbers until we reach the prime factors. The detailed steps include checking divisibility by 2, 3, 5, and finally 7.
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