To solve this problem, let's use variables to represent the number of quarters and nickels that Ellen has. Let's say Ellen has q quarters and n nickels. From the given information, we know that Ellen has $6.30 in quarters and nickels. Since each quarter is worth $0.25, we can write an equation: 0.25q + 0.05n = 6.30.
We also know that Ellen has 6 less nickels than quarters. We can write the second equation: n = q - 6.
Now, let's solve the system of equations to find the values of q and n. Substituting the value of n from the second equation into the first equation, we get: 0.25q + 0.05(q - 6) = 6.30. Simplifying this equation, we get: 0.30q - 0.30 = 6.30. Solving this equation, we find that q = 24.
Now we can substitute the value of q back into the second equation to find the value of n: n = 24 - 6 = 18. Therefore, Ellen has 24 quarters and 18 nickels.
Since Lola has twice as many quarters as Ellen, Lola has 2 * 24 = 48 quarters. And since Lola has half as many nickels as Ellen, Lola has 1/2 * 18 = 9 nickels. Therefore, Lola has $0.25 * 48 + $0.05 * 9 = $12 + $0.45 = $12.45.
Lola has twice as many quarters as Ellen and half as many nickels as Ellen. Ellen has $6.30 in quarters and nickels and has 6 fewer nickels than quarters.
Let's start by defining the variables:
Let x be the number of quarters Ellen has.
Then, 2x would be the number of quarters Lola has.
Also, (x-6) would be the number of nickels Ellen has because she has 6 fewer nickels than quarters.
And, (1/2)(x-6) would be the number of nickels Lola has because she has half as many nickels as Ellen.
Now, let's set up the equation:
$6.30 = 0.25x + 0.05[(1/2)(x-6)]
Simplify and solve for x:
$6.30 = 0.25x + 0.025x - 0.15
$6.30 = 0.275x - 0.15
0.275x = $6.30 + 0.15
0.275x = $6.45
x = $6.45 / 0.275 = $23.45
So, Ellen has $23.45 in quarters and Lola has twice as many quarters, which is $23.45 x 2 = $46.90. Therefore, Lola has $46.90.
Lola has a total of $11.40, consisting of 44 quarters and 8 nickels. Ellen has 22 quarters and 16 nickels, which forms the basis of the calculation. This was derived through a system of equations based on the relationships between their coins.
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