Five times the sum of three consecutive integers is 150. What are the integers?

Let x=1st integer x+1=2nd integer x+2=3rd integer
5(x+x+1+x+2)=150 5(3x+3)=150 15x+15=150 15x=135 x=9
So you put what x is 1st integer (x)= 9 Since it's three consecutive integers, you add one to the 2nd integer 2nd integer (x+1)= 10 Then you do the same thing for the third integer 3rd integer (x+2)= 11

Answered by tylolsmart | 2024-06-10

5(x+(x+1)+(x+2))=150
5(3x+3)=150
15x+15=150
15x=135
x=9
Your three consecutive integers are 9, 10, and 11.

Answered by DMBZarate | 2024-06-10

The three consecutive integers are 9, 10, and 11. We find these by setting up an equation based on the problem statement. By solving for x , we determine the integers in succession.
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Answered by tylolsmart | 2024-09-30