The equation is 54=(n)+(n+1)+(n+2)
Which simplifies to 54=3n+3
Subtract 3 from each side to get 51=3n
Divide each side by 3 to get 17=n
Then you substitute 17 for n to get 17 (n) and 18 (n+1) and 19 (n+2).
Three consecutive numbers with a** sum **of 54 are 17, 18, and 19 if the sum of three **consecutive **numbers is 54.
What is a linear equation?
It is defined as the relation between two variables , if we plot the graph of the linear **equation **we will get a straight line.
If in the linear equation , one variable is present, then the **equation **is known as the **linear **equation in one variable .
It is given that:
Three **consecutive **numbers with a sum of 54.
Let the consecutive numbers are x, (x + 1), (x + 2)
x + (x + 1) + (x + 2) = 54
3x + 3 = 54
3x = 51
x = 17
x + 1 = 17 + 1 = 18
x + 2 = 17 + 2 = 19
Thus, three consecutive numbers with a** sum **of 54 are 17, 18, and 19 if the sum of three **consecutive **numbers is 54.
Learn more about the **linear equation **here:
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The three consecutive integers that sum to 54 are 17, 18, and 19. We defined the integers as x, x + 1, and x + 2, leading us to the equation 3x + 3 = 54, which simplifies to x = 17. Therefore, the numbers are 17, 18, and 19.
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