So,
123/20 is over 1. The denominator is 20, so what I would do is find out how many *whole *20's would fit in 123.
The result is that 6 20's would fit in 123 with 3 left over.
The answer is six and three-twentieths (6 3/20). It's already in simplest form.
The improper fraction 20 123 converts to the mixed number 6 20 3 . This is found by dividing the numerator by the denominator to get the whole part and using the remainder for the fractional part. Thus, the final answer is 6 20 3 .
;