A 13-ounce package of pistachios costs $5.99. What is the unit rate?

Question

sissyrose · Answer

The unit rate is $0.46 per ounce because $5.99/13oz=$0.46/oz.

calculista · Answer

we know that 
 A rate is a ratio that compares quantities in different units. A unit rate is a rate where the second quantity is one unit 
 so 
 In this problem to find the unit rate 
 Divide $ 5.99 by 13 o u n ces 
 u ni t r a t e = 13 5.99 ​ o u n ce d o ll a rs ​ u ni t r a t e = 0.46 o u n ce d o ll a rs ​ 
 therefore 
 the answer is 
 the unit rate is equal to 0.46 o u n ce d o ll a rs ​

calculista · Answer

The unit rate of the pistachios is approximately $0.46 per ounce, which reflects the cost for each ounce of product purchased. To find this, the total price of $5.99 was divided by the weight of 13 ounces. Therefore, the answer is expressed as dollars per ounce. 
 ;

A 13-ounce package of pistachios costs $5.99. What is the unit rate?

Answer (3)

Related Questions in Mathematics

📝 Answered - Select the correct answer. Which equation is equivalent to the given equation? [tex]$x^2-6 x=8$[/tex] A. [tex]$(x-6)^2=44$[/tex] B. [tex]$(x-3)^2=17$[/tex] C. [tex]$(x-6)^2=20$[/tex] D. [tex]$(x-3)^2=14$[/tex]

📝 Answered - Which phrase best describes the translation from the graph [tex]y=6 x^2[/tex] to the graph of [tex]y=6(x+1)^2[/tex]? A. 6 units left B. 6 units right C. 1 unit left D. 1 unit right

📝 Answered - What expression is equivalent to [tex]$\left(5 z^2+3 z+2\right)^2$[/tex] ? A. [tex]$5 z^4+3 z^2+4$[/tex] B. [tex]$5 z^4+9 z^2+4$[/tex] C. [tex]$25 z^4+30 z^3+19 z^2+12 z+4$[/tex] D. [tex]$25 z^4+30 z^3+29 z^2+12 z+4$[/tex]

📝 Answered - The graph of [tex]y=\frac{5}{4} x+1[/tex] is shown below. The coordinate ([tex]0, y[/tex]) is a solution of the equation. Given the [tex]x[/tex]-value of 0, what is the value of the [tex]y[/tex]-coordinate for the coordinate ([tex]0, y[/tex])? [tex]y=[/tex] [blank]

📝 Answered - If [tex]f(-2)=0[/tex], what are all the factors of the function [tex]f(x)=x^3-2 x^2-68 x-120[/tex]? Use the Remainder Theorem. A. [tex](x+2)(x+60)[/tex] B. [tex](x-2)(x-60)[/tex] C. [tex](x-10)(x+2)(x+6)[/tex] D. [tex](x+10)(x-2)(x-6)[/tex]