The bases on a softball diamond are 60 feet apart. How far is it from home plate to second base?
Answer (2)
To find the distance from home plate to second base on a softball diamond, one must calculate the diagonal of a square with sides of 60 feet, using the Pythagorean theorem. The diagonal distance is the hypotenuse of a right-angled triangle, which is approximately 84.9 feet.
The question involves finding the distance between home plate and second base on a softball diamond, where the bases are 60 feet apart. To determine this distance, we can visualize the softball diamond as a square with each side measuring 60 feet. The diagonal of the square, which connects home plate to second base, can be calculated using the Pythagorean theorem, where the diagonal (d) is the hypotenuse of a right-angled triangle whose other two sides are the length and the width of the square (each 60 feet).
Applying the Pythagorean theorem:
dĀ² = 60Ā² + 60Ā²
dĀ² = 3600 + 3600
dĀ² = 7200
d = ā7200
d = 84.9 feet (rounded to one decimal place)
Therefore, the distance from home plate to second base is approximately 84.9 feet.
To find the distance from home plate to second base on a softball diamond, we use the Pythagorean theorem. The calculation shows that the distance is approximately 84.85 feet. This represents the diagonal of the square formed by the bases, each measuring 60 feet apart.
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