Solve the system of equations by substitution:

\[ Y = 3x - 13 \]
\[ 3x + 2Y = 19 \]

{ 3 x + 2 y = 19 y = 3 x − 13 ​ S u b s t i t u t i o n 3 x + 2 ( 3 x − 13 ) = 19 3 x + 6 x − 26 = 19 9 x − 26 = 19 ∣ a dd 26 9 x = 45 ∣ d i v i d e b y 9 x = 5 y = 3 x − 13 = 3 ∗ 5 − 13 = 15 − 13 = 2 x = 5 y = 2

Answered by luana | 2024-06-10

The **solution **to the **system **of **equations **is x = 5 and y = 2.
Given that:
The **system **of equations :
y = 3x - 13 (1)
3x + 2y = 19 (2)
Step 1: Solve **equation **(1) for Y:
y = 3x - 13
Step 2: Substitute y from **equation **(1) into equation (2):
3x + 2(3x - 13) = 19
Step 3: **Simplify **the **equation **and solve for x:
3x + 6x - 26 = 19
9x - 26 = 19
9x = 19 + 26
9x = 45
x = 45/9
x = 5
Step 4: **Substitute **x = 5 into **equation **(1) to find Y:
y = 3(5) - 13
y = 15 - 13
y = 2
So, the **values **of x and y are 5 and 2, respectively .
Learn more about **Equation **here:
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Answered by amardeepvt7 | 2024-06-18

The solution to the system of equations is ( 5 , 2 ) , derived by substituting the expression for Y into the second equation and solving for x and Y .
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Answered by luana | 2024-10-01