GuideFoot - Learn Together, Grow Smarter. Logo

In Mathematics / Middle School | 2014-11-17

Dr. Piegan treated 440 dogs. The percentage of obese dogs increased from 52.5% in 2010 to 55.0% in 2011. What was the percent increase?

Asked by princessluna450

Answer (3)

Well, the formula for finding percent change is or i g ina l am o u n t am o u n t o f c han g e ​ . So, the amount of change is 2.5 and original amount is 52.5. Then, to get the percent increase, you divide 2.5 by 52.5 which is 0.047619048. You multiply by 100 since its percent and get 4.7619048. But you should probably round to the nearest tenth ≈ 4.8%.

Answered by MarleneAlanis | 2024-06-10

To calculate the percent increase in the obesity rate of dogs treated by Dr. Piegan from 2010 to 2011, we can follow these steps:
First, determine the original percentage of obese dogs in 2010, which is 52.5 percent.
Next, identify the new percentage of obese dogs in 2011, which is 55.0 percent.
Subtract the original percentage from the new percentage: 55.0 percent - 52.5 percent = 2.5 percent.
Finally, divide the difference by the original percentage to find the percent increase: (2.5 percent / 52.5 percent) * 100 = 4.76 percent.
The percent increase of obese dogs from 2010 to 2011 is therefore approximately 4.76 percent.

Answered by AliceB123 | 2024-06-24

The percent increase in the percentage of obese dogs from 2010 to 2011 is calculated to be approximately 4.8%. This is done by determining the difference between the new and original percentages, then dividing by the original percentage and multiplying by 100. After calculations, the result shows a notable change in obesity rates in dogs.
;

Answered by MarleneAlanis | 2024-11-09