so xy=-1040 and x+y=109 a negative times a positive = a negative so x or y must be negative and only one
so xy=-1040 x+y=109 subtract x from both sides y=109-x subsitute y=109-x into xy=-1040
x(109-x)=-1040 109x-x^2=-1040 add x^2 to both sides 109x=-1040+x^2 subtract 109x from both sides x^2-109x-1040=0 put it in the quatdratic formula and get x=[{(7721)^(1/2)}+109]/2 or [{(7721)^(1/2)}-109]/2
The two numbers that multiply to -1040 and add to 109 are approximately 117.75 and -8.75. Both conditions of multiplication and addition are satisfied. This problem can be solved using the quadratic equation method.
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