Six consecutive whole numbers are each divided by 6. Find the sum of the resulting six remainders.

FYI this is the english section, not math. anyway.
6 consectuve whole numbers are each divided by 6. find the sum of the resulting 6 remainders
so x, x+1, x+2, x+3, x+4, x+5 lets say that x=6 first one=no remainder 2nd=Remainder=1 3rd,R=2 4th R=3 5th R=4 6th R=5
addthem all tother (1+2+3+4+5) and get 15
if x=1 then 1st R=1 2nd R=2 3rd R=3 4th R=4 5th R=5 6th R=0 notice that we get 1+2+3+4+5 same as the first equation so the answer sill always be 15

Answered by apologiabiology | 2024-06-10

When six consecutive whole numbers are divided by 6, their remainders sum to a constant value of 15. Regardless of where we start with the first number, the remainders will cycle through 0 to 5, always adding up to 15. Thus, for any set of six consecutive numbers, the sum of the remainders after dividing by 6 is always 15.
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Answered by apologiabiology | 2024-10-12