A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3 m/s\(^2\)?
Given:
\[ F = ? \]
\[ M = 10 \, \text{kg} \]
\[ A = 3 \, \text{m/s}^2 \]
Answer (3)
The force is 30 Newton
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A 10 kg bowling ball would require. What force to accelerate down an alleyway at a rate of 3 m/sĀ² ?
We have the following data:
F (force) = ? (in N or kg.m/sĀ²)
m (mass) = 10 kg
a (acceleration) = 3 m/sĀ²
We apply the data to the Net force formula, we have:
F = m ā a
F = 10 k g ā 3 s 2 m ā
F = 30 k g ā s 2 m ā ā F = 30 N ā ā ā
The force required to accelerate an object can be calculated using Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, the mass of the bowling ball is 10 kg and the acceleration is 3 m/sĀ².
Therefore, the force required can be calculated by multiplying the mass and the acceleration:
F = m x a
F = 10 kg x 3 m/sĀ² = 30 N
So, a 10 kg bowling ball would require 30 Newtons of force to accelerate down an alleyway at a rate of 3 m/sĀ².
The force required to accelerate a 10 kg bowling ball at 3 m/sĀ² is 30 Newtons, calculated using the formula F = m * a. By substituting the given values into the formula, the result is straightforward. Thus, 30 N is needed for the desired acceleration.
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