How do you solve the system of equations using the elimination method?

1. \(5x - 4y = 42\)
2. \(x - 6y = 24\)

5x - 4y = 42 ------ (1) x - 6y = 24 ----------(2), multiply eq. 2 by 5 we get 5x - 30y = 120 -----(3), now use eq. (3) - (1), 5x - 30y = 120 -(5x - 4y = 42) - 30y + 4y = 120 - 42, -26y = 78, y = -78/26 = -3, x = 24 + 6y = 24 + (6*[-3]) = 24 - 18 = 6, x = 6, y = -3.
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Answered by here2help | 2024-06-10

By multiplying the second equation to align the coefficients of x , and then subtracting, we found that y = − 3 . Substituting y back into one of the original equations gives us x = 6 . Thus, the solution to the system of equations is x = 6 and y = − 3 .
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Answered by here2help | 2024-12-26