Solve using elimination:

\[ 2x + 5y = 2 \]
\[ 3x - 5y = 53 \]

2x + 5y =2 (+) 3x - 5y =53
5x + 0 = 55
Then finish it.
5x = 55 x = 11
Substitute x = 11,
2(11) + 5y = 2 22 - 2 + 5y = 0 20 + 5y = 0 5y = -20 y= -4

Answered by Anonymous | 2024-06-10

2x+5y=2 3x-5y=53

2x+3x=2+53 5x=55 / : 5 x=11

x=11 3x-5y=53
x=11 3*11-5y=53
x=11 33-5y=53
x=11 -5y=53-33
x=11 -5y=20 / : (-5)
x=11 y=-4

Answered by vivindalka | 2024-06-10

Using elimination, we solved the equations 2 x + 5 y = 2 and 3 x − 5 y = 53 to find x = 11 and y = − 4 . We added the two equations to eliminate y , which allowed us to solve for x , and then substituted back to find y . The solution to the system is ( 11 , − 4 ) .
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Answered by vivindalka | 2024-10-01