What is the smallest number in the following order:

7.7, 7.77, 7.17, 7.707?

in order 7.17 7.7 7.77 7.707

Answered by cristinanazario | 2024-06-10

The numbers in **ascending **order from **smallest **to largest are:
{7.17, 7.7, 7.707, 7.77}. The smallest **number **is 7.17.
To find the smallest number , compare the **decimal **digits from left to right.
Examine each **number **digit by digit:
The **number **7.7 has one **decimal **digit, the digit after the decimal **point **is 7.
The number 7.77 has two decimal digits, the digit after the decimal point is 7, and the next **digit **is also 7.
The **number **7.17 has two **decimal **digits, the digit after the decimal **point **is 1, which is smaller than 7.
The number 7.707 has three decimal digits , the digit after the **decimal **point is 7, the next digit is also 7, and the third digit is 0.
To compare the numbers , first look at the whole part, which is 7 for all of them.
Compare the first **decimal **digit:
In this case, 7.17 is the **smallest **because the digit 1 in the **tenths **place is **smaller **than 7, and 7 in the other numbers.
So, the smallest **decimal **number is 7.17.
Learn more about Decimal number here:
https://brainly.com/question/33109985
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Answered by amardeepvt7 | 2024-06-18

The smallest number among 7.7, 7.77, 7.17, and 7.707 is 7.17. This is determined by comparing the decimal digits, where 7.17 has a smaller tenths place digit than the others. Hence, 7.17 is the smallest of the four values.
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Answered by amardeepvt7 | 2024-09-30