Halle solved [tex]\frac{664}{48}[/tex]. She got a quotient of 13 with a remainder of 40. How could she use her work below to solve [tex]\frac{664}{48}[/tex] without redoing the work? Explain your thinking.
Work shown:
\[
\begin{array}{c}
48 \, | \, 664 \\
\underline{ \quad 644 \quad } \\
\quad - \, 48 \\
\hline
\quad \, \, 184 \\
\quad - \, 144 \\
\hline
\quad \, \, \, 40 \\
\end{array}
\]
Answer (2)
664/48=332/24=166/12=83/6,
83/6=78/6+5/6=13+5/6
Therefore,
664/48=13+5/6
Halle can use her quotient of 13 and remainder of 40 to express 48 664 as 13 + 48 40 . She can simplify 48 40 to 6 5 , giving her the final answer of 13 + 6 5 . This approach allows her to utilize her earlier calculations without starting over.
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