What is the axis of symmetry for [tex]f(x) = -5x^2 - 20x - 10[/tex]?

For this case we have the following function: f ( x ) = − 5 x 2 − 20 x − 10 To find the axis of symmetry, the first thing to do is to derive the function. We have then:
f ′ ( x ) = − 10 x − 20 Equaling zero we have:
− 10 x − 20 = 0 We clear the value of x.
We have then:
[tex]-10x = 20
x = -20/10
x = -2 [/tex] ** Answer: **
** The axis of symmetry is given by: **
** x = -2**

Answered by carlosego | 2024-06-11

x= -2 is the axis of symmetry for f ( x ) = − 5 x 2 − 20 x − 10 ;

Answered by OrethaWilkison | 2024-06-12

The axis of symmetry for the function f ( x ) = − 5 x 2 − 20 x − 10 is x = − 2 . This is found using the formula x = − 2 a b ​ with coefficients from the quadratic function.
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Answered by carlosego | 2024-10-02