Bx+Cy=D -- subtract Bx
Cy=D-Bx -- divide by C
y=(D-Bx)/C
Bx + Cy = D
Solve for y . . .
*subtract Bx from both sides
Bx - Bx + Cy = D - Bx
Cy = D - Bx
*now divide both sides by C
Cy/C = (D - Bx)/C
Cy/C = D/C - Bx/C
y = D/C - (B/C)x
y = -(B/C)x + D/C
To solve for y in the equation B x + C y = D , isolate C y by subtracting B x and then divide by C . The final equation is y = − C B x + C D .
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