so perimeter < 556 permiter=2Legnth+2Width so perimiter=2(legnth+width)
556/2 > Legnth+width 228 > legnth +width legnth =150 so 228 > 150+width subtract 150 from both sides 78 > width width cand be 78 or less but not 0 or negative
anoth way to do it is 556 > 2(150)+2width 556 > 300+2width subtract 300 from both sides 256 > 2width divide both sides by 2 78 > width
The possible widths for the rectangle must be greater than 0 and up to 128 inches. Thus, the width can range from just above 0 to 128 inches. This is expressed as 0 < W ≤ 128.
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