Soo-Jin and Mary had an equal number of beads. After Soo-Jin gave 54 beads to Mary, Mary had 7 times as many beads as Soo-Jin. How many beads did they have altogether?

x\ \ \rightarrow\ \ the\ number\ of\ Soo-Jin's\ beads\\y\ \ \rightarrow\ \ the\ number\ of\ Mary's\ beads\\\\x=y\ \ \ \ \ and\ \ \ \ \ 7\cdot(x-54)=y+54\\\\7x-7\cdot54=x+54\\7x-7\cdot54-x+7\cdot54=x+54-x+7\cdot54\\6x=8\cdot54\ \ /:6\\\\x= \frac{\big{8\cdot54}}{\big{6}} \\\\x= 8\cdot9\\\\x=72\ \ \ \Rightarrow\ \ \ y=72\ \ \ \Rightarrow\ \ \ x+y=2\cdot72=144\\\\Ans.\ \ \ 144\ beads\ altogether

Answered by kate200468 | 2024-06-10

i cant really get the specific answer but i guess that both of them have 55.96 and then Soo-jin gave 54 to Mary and it left 1.96 so Mary had 109.96 ....1.96(7 times) is exactly 111.120some so ...i think altogether they have is 111.92..that is all i can think for this question.hope it help.

Answered by dawtlenpar99 | 2024-06-10

Soo-Jin and Mary each had 72 beads originally. Together, they had a total of 144 beads. This total is determined by calculating their individual amounts after the transfer of beads occurred.
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Answered by kate200468 | 2024-10-15