What is the value of \( x \) in this equation?
\[ \sqrt{3\sqrt{x+1}} = \sqrt{3x-5} \]
Answer (3)
3 x + 1 = 3 x − 5 3 ( x + 1 ) = 3 x − 5 ∣ 2 3 ( x + 1 ) = 3 x − 5 3 x + 3 = 3 x − 5 ∣ s u b t r a c t 3 x 3 = − 5 T h ere a re n o so l u t i o n s .
To solve for x in the equation √3√x+1 = √3x-5, square both sides to eliminate square roots, rearrange to form a quadratic equation, and solve for x using the** quadratic formula **or factoring. Ensure solutions are valid by checking against the original equation. ;
To find the value of x in the equation 3 x + 1 = 3 x − 5 , square both sides to eliminate square roots, leading to a quadratic equation. Then, use the quadratic formula to solve for x and check the solutions for validity. Finally, confirm which solutions satisfy the original equation.
;
