The question involves solving a system of equations based on the given information: there are 5 more crows than cows and a total of 52 legs on all the animals in a farm field. We can set up two equations to represent this scenario. Let's denote the number of cows as c and the number of crows as r. Cows have 4 legs and crows have 2, so we can set up the following equations:
r = c + 5 (because there are 5 more crows than cows)
4c + 2r = 52 (because the total number of legs is 52)
Now we substitute the first equation into the second equation:
4c + 2(c + 5) = 52
4c + 2c + 10 = 52
6c + 10 = 52
6c = 52 - 10
6c = 42
c = 42 / 6
c = 7 (the number of cows)
Then we find the number of crows:
r = 7 + 5 = 12 (the number of crows)
So, there are 7 cows and 12 crows in the farm field.
There are 7 cows and 12 crows in the farm field, determined by setting up and solving a system of equations based on the given conditions. The equations account for the difference in the number of crows relative to cows and the total number of legs from both types of animals. By solving these equations, we can find the quantities of each animal present.
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