Write a real-world problem that could be modeled by a linear function whose x-intercept is 5 and y-intercept is 60.

The y-intercept is 60 so say you start with 60 apples. And the x-intercept is 5 so lets say you eat them all in 5 days. So the equation would look somthing like this Y = − 12 x + 60 and would end up having a word problem that says somthing like "Jimmy has 60 apples and eats 12 a day how many days go by before Jonny has no more apples ?"

Answered by conungi | 2024-06-10

The real-world problem that could be **modeled **by a **linear function **will be y = 60 - 12x.
What is a linear equation?
A **connection **between a number of variables results in a **linear **model when a graph is displayed. The **variable **will have a **degree **of one.
The **linear **equation is given as,
x/a + y/b = 1
Where 'a' is the x -**intercept **of the line and ‘b’ is the y-intercept of the line.
The linear function whose x-intercept is 5 and y-intercept is 60. Then the equation is given as,
x/5 + y/60 = 1
**Convert **the equation into a slope -**intercept **form. Then we have
x/5 + y/60 = 1
12x + y = 60
y = 60 - 12x
The real-world problem that could be **modeled **by a **linear function **will be y = 60 - 12x.
More about the linear equation link is given below.
https://brainly.com/question/11897796
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Answered by jainveenamrata | 2024-06-16

A real-world problem can involve a candle business with overhead costs of $60 when no candles are sold, decreasing costs by $12 for each candle produced, leading to the linear function y = 60 - 12x. This function illustrates how costs relate to the number of candles sold, with the x-intercept at 5. The model emphasizes the importance of balancing production and covering costs for the business.
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Answered by jainveenamrata | 2024-10-01