The sum of the digits of a two-digit number is 11. The tens digit is one less than three times the ones digit. Find the original number.
Answer (2)
\ \ \ \ x=3y-1\\\\ 3y-1+y=11\\ 4y-1=11\ \ \ | add\ 1\\ 4y=12\ \ \ | divide\ by\ 4\\ y=3\\\\ x=8\\\\ Original\ number \ is\ 83."> x + y = 11 x + 1 = 3 y − − − > x = 3 y − 1 3 y − 1 + y = 11 4 y − 1 = 11 ∣ a dd 1 4 y = 12 ∣ d i v i d e b y 4 y = 3 x = 8 O r i g ina l n u mb er i s 83.
The two-digit number is 83, which meets the criteria of having a digit sum of 11 and the tens digit being one less than three times the ones digit.
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